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Remove a JavaScript array element by deciding whether the operation targets one position or every matching record. Splice and filter support different behaviors, and neither should be chosen solely because it makes the visible result look right.
Remove a JavaScript array element at a reviewed index
array.splice(index, 1) removes one element in place and returns an array of removed elements. Confirm the index before calling it. Passing -1 when a search failed removes the last element, which can silently affect an unrelated record.

Use filter for a new matching collection
Filter returns a new array containing elements whose callback passes. A condition that excludes an identifier can remove multiple matching records, not only the first. It creates a new outer array but retains references to existing object elements.
Avoid delete when compact removal is needed
Using delete on an array element leaves an empty slot rather than compacting subsequent indexes. Select the operation that matches the business rule and test duplicate identifiers, a missing target and an empty array. Do not interpret a changed length as proof that the correct record was removed.
A practical checklist
- Define one-position versus matching-record removal.
- Validate any searched index before splice.
- Check filter behavior with duplicate identifiers.
- Avoid accidental holes from delete.
- Test missing targets and empty arrays.
Worked example
Illustrative example: a synthetic list contains identifiers 1, 2 and 2. Filtering out identifier 2 removes both matching records. If only one record should disappear, the code needs an explicit first-match rule and a guarded index-based operation instead.

Common questions
Does filter mutate the original outer array? No. Is splice's return value the remaining array? No; it contains removed elements. Does delete shift later elements together? No; it leaves a hole.
What to do next
Write the removal rule in a test before implementing it. Missing-target behavior should be explicit so an unsuccessful search never deletes a different record.
